Q: Print a 2D array in spiral order

const inputArray = [
  [1, 2, 3, 4],
  [5, 6, 7, 8],
  [9, 10, 11, 12],
  [13, 14, 15, 16],
];

const test = [1, 2, 3, 4, 8, 12, 16, 15, 14, 13, 9, 5, 6, 7, 11, 10];

// dir var
// 0 right
// 1 down
// 2 left
// 3 up

const printSpiral = (array, numRows, numCols) => {
  let top = 0,
    bottom = numRows - 1,
    left = 0,
    right = numCols - 1,
    dir = 0,
    values = [];

  while (top <= bottom && left <= right) {
    if (dir === 0) {
      for (var i = left; i <= right; i++) {
        values.push(array[top][i]);
      }
      top++;
      dir = 1;
    } else if (dir === 1) {
      for (var i = top; i <= bottom; i++) {
        values.push(array[i][right]);
      }
      right--;
      dir = 2;
    } else if (dir === 2) {
      for (var i = right; i >= left; i--) {
        values.push(array[bottom][i]);
      }
      bottom--;
      dir = 3;
    } else if (dir === 3) {
      for (var i = bottom; i >= top; i--) {
        values.push(array[i][left]);
      }
      left++;
      dir = 0;
    }
  }
  return values;
};

const answer = printSpiral(inputArray, 4, 4);

const test1 = answer.toString() === test.toString();

console.log('test1 pass? ', test1);